Math challenge - need help

am i that bad at maths? lol.. or was it that i was lazy to try.. lol.. guess u shud check this out in the mornin..

You can solve it then graphically using 2x+5y=90..

:)

Let

x=duck

y=chicken

z=bird

Given:

1. selling prices:

x=2

y=5

z=.1

2. Quantity:

x=?

y=?

z=100

Therefore the equation to get a total of 100 selling price is:

2x+5y+.1(100)=100

Simplify:

2x+5y+10=100

2x+5y=90

Then you can subsitute any number to the variable to get the combinations (mix) and have a total 100 riyals.

trick question - you have birds, ducks and chickens in the statement part of the question yet you only want the number of birds in the answer.

You said 10 birds cost 1 riyal but you want to know how you can have a mix of 100 birds for 100 Riyal. It's not possible because 100 birds would cost 10 riyal

~I know nothing!~

Sergeant Schults from Hogan's Heros

Ok, I assumed that 10 birds are the smallest "package" you can get because the price was 10 for 1 ryial.

And don't spend too much time looking for a 3rd equation. There is none! No way...you could draw it in a x/y-coordinate system, and see when you hit a natural (full) number...non other way of doing it IMO.

Hmmmm...

How did you come up with "you know that h can only be 10, 20, 30, 40, 50, 60, 70, 80 or 90..."?

By analogy? Can you come up with 3 equations for the 3 unknowns?

Okay, I'll get out of work now and see if I still have my math skill.

“They say you can't live without love. Tell them oxygen is more important!.”

- G. House 

so what more i could answer...?

give me the 100 riyals and ill give u a mix of 100 of birds... lolz...

and to end it: you know that

h= 100-47.37+1.579k

you know that h can only be 10, 20, 30, 40, 50, 60, 70, 80 or 90...

h=10, k=-26.99

h=20, k=-20.66

h=30, k=-14.33

h=40, k=-7.99

h=50, k=-1.66

h=60, k=4.66

h=70, k=11

h=80, k=17.33

h=90, k=23.66

h=70, k=11

j=47.37 - 2.579k = 19 :)

I try, had enough math in my studies...

If 10 birds are sold for one reyal, one duck is sold for 2 reyals and one chiken sells for 5 reyals

b= birds, d = ducks, c=chicken

h, j, k as the number you are looking for...

equations

h+j+k = 100 (100 animals)

h*0.1+j*2+k*5= 100 (100 ryial)

b=0.1

d=2

c=5

from the first equation, we can get: h = 100-j-k

put this in 2)

(100-j-k)*0.1+j*2+5*k=100

10-0.1j-0.1k+2j+5k=100

1.9j = 90 - 4.9k

j = 47.37 - 2.579k

Then, you have to solve it graphical...no way of doing it mathematical, with only 2 equations and 3 unknown numbers.

you need three equations from the given problem and eliminate per variable (x + y + z), that's what I remember in solving this one.

hi logicsays, i did it also by trial and error...

but i really want to know the equation---can you tell me of which lesson of algebra is your son now...

=========================

"liFe wAs lIkE a bOx oF cHocOlAtEs. yOu nEveR kNow

wHaT yOu'Re gOnNa gEt." ================================

Thank you for coming for the rescue

Thanks

Sorry.. I just used trial and error..and a page full of scribbling..

I am sure there is a X+y+z type equation..

Please advise how did you work the equations ?

The answer is 70 birds = 7 Riyals

19 ducks = 38 Riyals

and 11 chickens = 55 Riyals

Total 100 = 100

Hope it can help. :)

Woudl you please tell me how you came out with the answer, I have been trying for an hour now to get the equations right but with no luck

70 birds = 7 riyals

19 ducks = 38 riyals

11 chicken = 55 riyals

=========================

"liFe wAs lIkE a bOx oF cHocOlAtEs. yOu nEveR kNow

wHaT yOu'Re gOnNa gEt." ================================

This is the cahllenge, the answer you got cost 100 reyals but not 100 animal, the challenge is to get eaxctely 100 anumal for the cost of 100 reyals ... what a challenge.. what will my son say about me ...!

indlad, 17+7+10=100?

17 chickens, 7ducks & 10 birds

to buy exactely a mix of 100 animals for a cost of 100 reyals given the above cost of each type of birds

what is required?