Mathematics (URGENT)

Heeey frnds,I have got some questions in maths but i could n't find the answer for that can any one help, and tell me how to find that?

a)A 68.03kg skater experiences 18.37 kg of friction when skating on a dry steel surface.Then, how to find the constant??? (corrected up to 2 decimal places)

b)Then ,write a direct variation equation for this situation

THEN AFTER ALL,, CAN U HELP ME TO KNOW HOW TO DO ALL THESE?????

-thnks

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By anonyalkult• 14 Sep 2009 11:55

Brushing up some old physics....

Friction = weight x constant

18.37 = 68.03 x constant

This gives constant = 18.37/68.03 = 0.27

Didnt follow the second question.

By anonyalkult• 14 Sep 2009 11:52

Brushing up some old physics....

Friction = weight x constant

18.37 = 68.03 x constant

This gives constant = 18.37/68.03 = 0.27

Didnt follow the second question.

By Centcom Real Estate• 14 Sep 2009 11:51

Rating: 4/5

(a) 0.27

(b) f= 0.27W where f is frictional force and W is weight of skater

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Mathematics (URGENT)

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